参考文章：https://wally0813.github.io/exploit%20tech/ctf%20write%20up/2018/10/23/file_struct_flag/
之前在bctf中遇到一道three，是一个没有leak的堆题，现在没有leak一股脑只能想到house of roman了，但是4096分之一的概率真的让人很痛苦。但是翻到出题人博客之后发现居然可以通过改写stdout来leak。
仔细复现之后，发现其中还设计到了一堆我不会的东西orz
首先是文件结构体的这个_flags，具体的定义为：
#define _IO_MAGIC 0xFBAD0000 /* Magic number */
#define _IO_MAGIC_MASK 0xFFFF0000
#define _IO_USER_BUF 0x0001 /* Don't deallocate buffer on close. */
#define _IO_UNBUFFERED 0x0002
#define _IO_NO_READS 0x0004 /* Reading not allowed. */
#define _IO_NO_WRITES 0x0008 /* Writing not allowed. */
#define _IO_EOF_SEEN 0x0010
#define _IO_ERR_SEEN 0x0020
#define _IO_DELETE_DONT_CLOSE 0x0040 /* Don't call close(_fileno) on close. */
#define _IO_LINKED 0x0080 /* In the list of all open files. */
#define _IO_IN_BACKUP 0x0100
#define _IO_LINE_BUF 0x0200
#define _IO_TIED_PUT_GET 0x0400 /* Put and get pointer move in unison. */
#define _IO_CURRENTLY_PUTTING 0x0800
#define _IO_IS_APPENDING 0x1000
#define _IO_IS_FILEBUF 0x2000
/* 0x4000 No longer used, reserved for compat. */
#define _IO_USER_LOCK 0x8000
而一个正常的stdout一般是这样的
_IO_MAGIC|_IO_IS_FILEBUF|_IO_CURRENTLY_PUTTING|_IO_LINKED|_IO_NO_READS | _IO_UNBUFFERED |_IO_USER_BUF
在这种情况下，就算去改_IO_write_base也不会输出对应位置的字符串的，反而还会使stdout炸掉
例子：
可以看到第二次根本不会输出
那么在调用puts的过程中究竟发生了什么呢？
int
_IO_puts (const char *str)
{
int result = EOF;
size_t len = strlen (str);
_IO_acquire_lock (_IO_stdout);
if ((_IO_vtable_offset (_IO_stdout) != 0
|| _IO_fwide (_IO_stdout, -1) == -1)
&& _IO_sputn (_IO_stdout, str, len) == len
&& _IO_putc_unlocked ('\n', _IO_stdout) != EOF)
result = MIN (INT_MAX, len + 1);
_IO_release_lock (_IO_stdout);
return result;
}
#define _IO_sputn(__fp, __s, __n) _IO_XSPUTN (__fp, __s, __n)
可以看到这里实际上是调用了_IO_sputn 这个函数，当然这个_IO_sputn实际上就是一个宏，调用了stdout的虚表中的_IO_xsputn_t
继续来看
size_t
_IO_new_file_xsputn (FILE *f, const void *data, size_t n)
{
const char *s = (const char *) data;
size_t to_do = n;
int must_flush = 0;
size_t count = 0;
if (n <= 0)
return 0;
/* This is an optimized implementation.
If the amount to be written straddles a block boundary
(or the filebuf is unbuffered), use sys_write directly. */
/* First figure out how much space is available in the buffer. */
if ((f->_flags & _IO_LINE_BUF) && (f->_flags & _IO_CURRENTLY_PUTTING))
{
count = f->_IO_buf_end - f->_IO_write_ptr;
if (count >= n)
{
const char *p;
for (p = s + n; p > s; )
{
if (*--p == '\n')
{
count = p - s + 1;
must_flush = 1;
break;
}
}
}
}
else if (f->_IO_write_end > f->_IO_write_ptr)
count = f->_IO_write_end - f->_IO_write_ptr; /* Space available. */
/* Then fill the buffer. */
if (count > 0)
{
if (count > to_do)
count = to_do;
f->_IO_write_ptr = __mempcpy (f->_IO_write_ptr, s, count);
s += count;
to_do -= count;
}
if (to_do + must_flush > 0)
{
size_t block_size, do_write;
/* Next flush the (full) buffer. */
if (_IO_OVERFLOW (f, EOF) == EOF)
/* If nothing else has to be written we must not signal the
caller that everything has been written. */
return to_do == 0 ? EOF : n - to_do;
/* Try to maintain alignment: write a whole number of blocks. */
block_size = f->_IO_buf_end - f->_IO_buf_base;
do_write = to_do - (block_size >= 128 ? to_do % block_size : 0);
if (do_write)
{
count = new_do_write (f, s, do_write);
to_do -= count;
if (count < do_write)
return n - to_do;
}
/* Now write out the remainder. Normally, this will fit in the
buffer, but it's somewhat messier for line-buffered files,
so we let _IO_default_xsputn handle the general case. */
if (to_do)
to_do -= _IO_default_xsputn (f, s+do_write, to_do);
}
return n - to_do;
}
libc_hidden_ver (_IO_new_file_xsputn, _IO_file_xsputn)
这里先判断了一堆缓冲区还够不够输出之类的，之后调用到了_IO_OVERFLOW
int
_IO_new_file_overflow (FILE *f, int ch)
{
if (f->_flags & _IO_NO_WRITES) /* SET ERROR */
{
f->_flags |= _IO_ERR_SEEN;
__set_errno (EBADF);
return EOF;
}
/* If currently reading or no buffer allocated. */
if ((f->_flags & _IO_CURRENTLY_PUTTING) == 0 || f->_IO_write_base == NULL)
{
/* Allocate a buffer if needed. */
if (f->_IO_write_base == NULL)
{
_IO_doallocbuf (f);
_IO_setg (f, f->_IO_buf_base, f->_IO_buf_base, f->_IO_buf_base);
}
/* Otherwise must be currently reading.
If _IO_read_ptr (and hence also _IO_read_end) is at the buffer end,
logically slide the buffer forwards one block (by setting the
read pointers to all point at the beginning of the block). This
makes room for subsequent output.
Otherwise, set the read pointers to _IO_read_end (leaving that
alone, so it can continue to correspond to the external position). */
if (__glibc_unlikely (_IO_in_backup (f)))
{
size_t nbackup = f->_IO_read_end - f->_IO_read_ptr;
_IO_free_backup_area (f);
f->_IO_read_base -= MIN (nbackup,
f->_IO_read_base - f->_IO_buf_base);
f->_IO_read_ptr = f->_IO_read_base;
}
if (f->_IO_read_ptr == f->_IO_buf_end)
f->_IO_read_end = f->_IO_read_ptr = f->_IO_buf_base;
f->_IO_write_ptr = f->_IO_read_ptr;
f->_IO_write_base = f->_IO_write_ptr;
f->_IO_write_end = f->_IO_buf_end;
f->_IO_read_base = f->_IO_read_ptr = f->_IO_read_end;
f->_flags |= _IO_CURRENTLY_PUTTING;
if (f->_mode <= 0 && f->_flags & (_IO_LINE_BUF | _IO_UNBUFFERED))
f->_IO_write_end = f->_IO_write_ptr;
}
if (ch == EOF)
return _IO_do_write (f, f->_IO_write_base,
f->_IO_write_ptr - f->_IO_write_base);
if (f->_IO_write_ptr == f->_IO_buf_end ) /* Buffer is really full */
if (_IO_do_flush (f) == EOF)
return EOF;
*f->_IO_write_ptr++ = ch;
if ((f->_flags & _IO_UNBUFFERED)
|| ((f->_flags & _IO_LINE_BUF) && ch == '\n'))
if (_IO_do_write (f, f->_IO_write_base,
f->_IO_write_ptr - f->_IO_write_base) == EOF)
return EOF;
return (unsigned char) ch;
}
libc_hidden_ver (_IO_new_file_overflow, _IO_file_overflow)
其中就有一句
if (ch == EOF)
return _IO_do_write (f, f->_IO_write_base,
f->_IO_write_ptr - f->_IO_write_base);
这里如果_IO_CURRENTLY_PUTTING为1的话，程序就会直接下来调用输出函数，为了不让_IO_new_file_xsputn函数中那次字符串拷贝干扰到leak，就可以直接修改_IO_write_base的值并且让_IO_CURRENTLY_PUTTING为1(虽然在stdout中这个值本来就是1)
而_IO_do_write里面也还有一点东西
int
_IO_new_do_write (FILE *fp, const char *data, size_t to_do)
{
return (to_do == 0
|| (size_t) new_do_write (fp, data, to_do) == to_do) ? 0 : EOF;
}
libc_hidden_ver (_IO_new_do_write, _IO_do_write)
static size_t
new_do_write (FILE *fp, const char *data, size_t to_do)
{
size_t count;
if (fp->_flags & _IO_IS_APPENDING)
/* On a system without a proper O_APPEND implementation,
you would need to sys_seek(0, SEEK_END) here, but is
not needed nor desirable for Unix- or Posix-like systems.
Instead, just indicate that offset (before and after) is
unpredictable. */
fp->_offset = _IO_pos_BAD;
else if (fp->_IO_read_end != fp->_IO_write_base)
{
off64_t new_pos
= _IO_SYSSEEK (fp, fp->_IO_write_base - fp->_IO_read_end, 1);
if (new_pos == _IO_pos_BAD)
return 0;
fp->_offset = new_pos;
}
count = _IO_SYSWRITE (fp, data, to_do);
if (fp->_cur_column && count)
fp->_cur_column = _IO_adjust_column (fp->_cur_column - 1, data, count) + 1;
_IO_setg (fp, fp->_IO_buf_base, fp->_IO_buf_base, fp->_IO_buf_base);
fp->_IO_write_base = fp->_IO_write_ptr = fp->_IO_buf_base;
fp->_IO_write_end = (fp->_mode <= 0
&& (fp->_flags & (_IO_LINE_BUF | _IO_UNBUFFERED))
? fp->_IO_buf_base : fp->_IO_buf_end);
return count;
}
可以看到，如果_IO_IS_APPENDING不是1的话，会对文件指针进行校准，这当然不是我们想看到的，校准之后的结果就是我们啥结果都看不到。所以为了leak，还需要修改这一位的值。
来测试一下：
很开心的看到了leak
总结下来，用这个方法leak的核心就是_IO_IS_APPENDING这个flag的值，将这个flag搞成1之后，就可以通过修改_IO_buf_base来完成leak。
而在赛题中，只需要爆破半个字节就可以拿到stdout的地址，然后从stdout开头开始覆盖，改掉flag之后再低位覆盖_IO_buf_base就可以完成leak，中间的三个变量在输出的过程中都不怎么用得到，直接盖成0就行了。
当然，这个全部得益于tcache没有检查的特点:)。